Resistance Series-Parallel Circuits
· 05.05.2011 · 11:33:51 ··· ··· Thursday ·· 4 (4)
kingdeadly1 I used one 1kohm resistor in series with two 10kohm resistors in parallel, which is also connected to another two 10kohm resistors in parallel. The Re of two 10kohm resistors in parallel is 5kohm. Therefore I have a resistance total of 11kohm.
R1 = 1kohm (in series)
R2 = 10kohm and R3 = 10kohm (in parallel)
R4 = 10kohm and R5 = 10kohm (in parallel)
R2 and R3 = R4 and R5 = 5kohm which can be calculated as follows:
Re1 = (R4 * R5)/(R4 + R5) = 5kohm
Re2 = (R2 * R3)/(R2 + R3) = 5kohm
R1 = 1kohm
Therefore:
RT = R1 + Re1 + Re2 = 11kohm
Or we can calculate that:
Re1 = Re2 = 10kohm/2resistors = 5kohm
· 01.01.1970 · 01:00:00 ···
0**##
· 01.01.1970 · 01:00:00 ···
# · 01.01.1970 · 01:00:00 ···
* · 01.01.1970 · 01:00:00 ···
* · 01.01.1970 · 01:00:00 ···
********
